PH255 Spring 2011
yay
there is an extra zero in problem3 @ (6).....the answer should be (1.00504-1)mc^2=.00504
there is another boo-boo on problem 15; i calculated it a few times thinking i was wrong but i got the same answer everytime. K=104.8keV or 105keV for kila-electron-Volts not Mega.
whoops i mean K=.1048 keV or .105keV
How many formula sheets can we have for the final?
on 15, mc^2 = 511keV, not 0.511keV like the solution states, which gives K = 0.105MeV
if that is the case then K = 0.105MeV is the correct solution
Mr. Warren is right, the electron mass-energy was quoted incorrectly. K=0.105MeV is the right answer.Problem 3 is fixed as well, extra zero removed.You're allowed 2 sheets front and back, as stated previously.
@ Eq. 20 -- should we have c^2 divided by v, instead of by v^2?
Yes, Eq. 20 should be c^2/v, not c^2/v^2
yay
ReplyDeletethere is an extra zero in problem3 @ (6).....the answer should be (1.00504-1)mc^2=.00504
ReplyDeletethere is another boo-boo on problem 15; i calculated it a few times thinking i was wrong but i got the same answer everytime. K=104.8keV or 105keV for kila-electron-Volts not Mega.
ReplyDeletewhoops i mean K=.1048 keV or .105keV
ReplyDeleteHow many formula sheets can we have for the final?
ReplyDeleteon 15, mc^2 = 511keV, not 0.511keV like the solution states, which gives K = 0.105MeV
ReplyDeleteif that is the case then K = 0.105MeV is the correct solution
ReplyDeleteMr. Warren is right, the electron mass-energy was quoted incorrectly. K=0.105MeV is the right answer.
ReplyDeleteProblem 3 is fixed as well, extra zero removed.
You're allowed 2 sheets front and back, as stated previously.
@ Eq. 20 -- should we have c^2 divided by v, instead of by v^2?
ReplyDeleteYes, Eq. 20 should be c^2/v, not c^2/v^2
ReplyDelete