PH255 Spring 2011

yay

there is an extra zero in problem3 @ (6).....the answer should be (1.00504-1)mc^2=.00504

there is another boo-boo on problem 15; i calculated it a few times thinking i was wrong but i got the same answer everytime. K=104.8keV or 105keV for kila-electron-Volts not Mega.

whoops i mean K=.1048 keV or .105keV

How many formula sheets can we have for the final?

on 15, mc^2 = 511keV, not 0.511keV like the solution states, which gives K = 0.105MeV

if that is the case then K = 0.105MeV is the correct solution

Mr. Warren is right, the electron mass-energy was quoted incorrectly. K=0.105MeV is the right answer.Problem 3 is fixed as well, extra zero removed.You're allowed 2 sheets front and back, as stated previously.

@ Eq. 20 -- should we have c^2 divided by v, instead of by v^2?

Yes, Eq. 20 should be c^2/v, not c^2/v^2

yay

ReplyDeletethere is an extra zero in problem3 @ (6).....the answer should be (1.00504-1)mc^2=.00504

ReplyDeletethere is another boo-boo on problem 15; i calculated it a few times thinking i was wrong but i got the same answer everytime. K=104.8keV or 105keV for kila-electron-Volts not Mega.

ReplyDeletewhoops i mean K=.1048 keV or .105keV

ReplyDeleteHow many formula sheets can we have for the final?

ReplyDeleteon 15, mc^2 = 511keV, not 0.511keV like the solution states, which gives K = 0.105MeV

ReplyDeleteif that is the case then K = 0.105MeV is the correct solution

ReplyDeleteMr. Warren is right, the electron mass-energy was quoted incorrectly. K=0.105MeV is the right answer.

ReplyDeleteProblem 3 is fixed as well, extra zero removed.

You're allowed 2 sheets front and back, as stated previously.

@ Eq. 20 -- should we have c^2 divided by v, instead of by v^2?

ReplyDeleteYes, Eq. 20 should be c^2/v, not c^2/v^2

ReplyDelete